Points A(-1 y) and B(5 7) lies on a circle with centre 0(2 -3y) Find y
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Given (7,−9)d(11,3) and center (0,0) calculating distance between the center (0,0) and (7,−9) using distance formula,
D=
(0−7)
2
+(0+9)
2
=
49+81
=
130
Circles equation is (x−0)
2
+(y−0)
2
=
130
x
2
+y
2
=
130
------ (1)
Now putting p+(11,3) in the above eq
n
(1)
(11)
2
+(3)
2
−(
130
)
2
121+9=(
130
)
2
130=130
Since the equation is true, that point is also on the circle.
∴ both the points lies on a circle with center at the origin.
Also, the equation is
x
2
+y
2
=(
130
)
2
x
2
+y
2
=130
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