Points A(-3,-2),B(-6,a)C(-3,-4) and D(0,-1) are verticles of quadrilateral ABCD. Find a if a is negative and AB=CD
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Answer:
AB=CD
AB
2
=CD
2
(−6+3)
2
+(a+2)
2
=(0+3)
2
+(−1+4)
2
⇒9a
2
+4+4a=9+9⇒a
2
+4a−5=0
⇒a
2
−a+5a−5=0⇒a(a−1)+5(a−1)=0⇒(a−1)(a+5)=0
a=1or−5
According to the question
a is negative hence the value of a is −5
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