Points A and B are situated along the extended axis of 2 cm long bar magnet at a distance x and 2x cm respectively. From the pole nearer to the points, the ratio of the magnetic field at A and B will be [EAMCET 1984; CPMT 1986]
A) 4 : 1 exactly B) 4 : 1 approx. C) 8 : 1 exactly D) 8 : 1 approx.
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Answered by
19
B proportional to 1/ x cube
B1/B2 = (2x) cube / x cube = 8:1
B1/B2 = (2x) cube / x cube = 8:1
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8
Ratio of the magnetic field at A and B will be 8:1.
Total number of points = 2 = A and B (Given)
Length of the bar magnet = 2cm (Given)
Distance one = B1 = x (Given)
Distance two = B2 = 2x (Given)
For a magnet B =μ0/ 4π × 2M/x³
= B1/ B2
= (x1/x2)³
= (x/2x)³
= 1/8
Thus, the ratio of the magnetic field at A and B will be 8:1.
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