points A,B,C are collinear. If AC=10 BC=8 then find d(AB) considering all posibilities
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i) If A-B-C
d( A,B) = d(A,C) - d( B,C)
= 10 - 8
= 2
ii) If A-C-B
d(A,B) = d ( A,C) + d ( B,C)
= 10 + 8
= 18
d( A,B) = d(A,C) - d( B,C)
= 10 - 8
= 2
ii) If A-C-B
d(A,B) = d ( A,C) + d ( B,C)
= 10 + 8
= 18
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