points a b c are on a circle such that m(arc abc)=120°. find m angle abc
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m(arc AB) + m(arc BC) + m(arc AC) = 360° [Measure of a circle is 360°] ∴ 120° + 120° + m (arc AC) = 360° ∴ m(arc AC) = 120° ∴ arc AB = arc BC = arc AC ∴ seg AB ≅ seg BC ≅ seg AC [Corresponding chords of congruents arcs of a circle are congruent] ∴ ∆ABC is an equilateral triangle
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