Question

points A coordinates M, - 4 B coordinates - 2, and n C coordinate 0,2 are collinear if B lies between a and c such that AC is equal to 2BC calculate the value of M and n

Answer 1

Answer:

Which class question

Step-by-step explanation:

Answer 2

Step-by-step explanation:

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points.

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)²

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)²

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16=> x - 3 = + 8

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16=> x - 3 = + 8=> x = +11 or -5

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16=> x - 3 = + 8=> x = +11 or -5 => y = (7+3x)/4

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16=> x - 3 = + 8=> x = +11 or -5 => y = (7+3x)/4 = 10 or -2

A (3,4) and B(7,7) and C(x,y) or C'(x,y) are collinear points. AB = √[(7-3)²+(7-4)²] = 5AC = 10, given.Slope of AC = slope of AB = (7-4)/(7-3) = 3/4=> (y-4)/(x-3) = 3/4 --- (1)=> 4 y - 3 x = 7 --- (2)AC² = 10² = (y - 4)² + (x - 3)² = [ 3/4 * (x - 3) ]² + (x-3)² = (x-3)² * 25/16=> x - 3 = + 8=> x = +11 or -5 => y = (7+3x)/4 = 10 or -2C = (11, 10) and C' = (-5, -2)

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