points B,C and D lie on a straight line. AC is perpendicular to BD BC=6cm and BD=22cm. Triangle ABC has and area of 42cm^2
calculate the size of angle x
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Given : points B,C and D lie on a straight line. AC is perpendicular to BD
BC = 6 cm , BD = 22 cm Triangle ABC has and area of 42cm²
To Find : size of angle x
Solution:
Area of ΔABC = (1/2) * BC * AC
=> (1/2) * BC * AC = 42
=> (1/2) * 6 * AC = 42
=> AC = 14 cm
BD = BC + CD
=> 22 = 6 + CD
=> CD = 16 cm
Tan x = AC /CD
=> Tan x = 14/16
=> Tanx = 7/8
=> x = Tan⁻¹(7/8)
=> x = 41.186°
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Answered by
12
Answer:
41.2˚
Step-by-step explanation:
22+6=28
42-28=14
22-6=16
tan^-1(14/16)=41.2˚
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