Math, asked by vaishnavi9110, 4 months ago

points D and E are the midpoints of side AB and AC of triangle ABC respectively. point F is on ray ED such that ED=DF . Prove that AFBE is a parallelogram​

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Answered by Anonymous
43

Answer:

\huge\colorbox{yellow}{Given\:-}

D and E are the midpoints of side AB and AC of triangle ABC respectively.

\huge\colorbox{yellow}{To\:Prove\:-}

AFBE is a parallelogram

\huge\colorbox{yellow}{Proof\:-}

seg AB and seg EF are the diagonals of AFBE.

seg AD ≅ seg DB [Given]

seg DE ≅ seg DF [Given]

∴ Diagonals of AFBE bisect each other.

  \pink{∴ AFBE \:  \:  is   \: \: a   \: \: parallelogram}

\huge\colorbox{yellow}{Thank\:You}


Anonymous: apni zindagi jee lo
Answered by salonitanpure74
4

Answer:

Step-by-step explanation:

given:points D and E are midpoints of side AC of ∆ABC,point F is on ray ED such that ED=DF.

To Prove: That quadrilateral AFBE is a parallelogram.

Proof: seg AB and seg EF are diagonals of quadrilateral AFBE.

seg AD = seg DB ..... Given

seg ED = seg DE ..... Construction

 Diagonals of quadrilateral AFBE bisect each other

quadrilateral AFBE is a parallelogram ...by SAS test

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