Points E & F lie on a diagonal AC of a parallelogram ABCD such that AE=CF.What type of a quadrilateral is BFDE?
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BFDE IS A PARALLELOGRAM
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Step-by-step explanation:
In quadrilateral BFDE,
Given: AE=CF
To prove: BFDE is IIgm
Proof: In triangleAEB and triangleDFC
AE=CF(Given)
Angle1= Angle 2(Alternate interior angle)
AB=Dc(As ABCD is a IIgm)
by SAS, triangleAEB congruent triangle DFC
by CPCT,BE=DF
Similarly,DE=BF
Thus,in quadrilateral BFDE opposite sides are equal hence it is a parallelogram.--------(Hence proved)
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