Points E and F are midpoints of seg AB and
seg AC of ∆ABC respectively EF = 5.6, then find
the length of BC.
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Answer:Given,
AB=6 cm,BC=4.8 cm and CA=5.6 cm
D,E and F are the mid points of sides BC,CA and AB of △ABC
To find: The perimeter of △DEF
Given,
E and F are the midpoints of sides CA and AB
⇒AE=EC and AF=FD
∴
EC
AE
=
FB
AF
⇒EF=
2
1
BC[ By mid point theorem ]
⇒EF=
2
1
×4.8=2.4 cm
Similarly,
DE=
2
1
AB=
2
1
×6=3 cm
FD=
2
1
AC=
2
1
×5.6=2.8 cm
∴ Perimeter of △DEF=DE+EF+FD
=3+2.4+2.8
=8.2 cm
Step-by-step explanation:
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