Question

Points I, II and III in the following plot respectively correspond to
(Vₘₚ : most probable velocity)
(A) Vₘₚ of N₂ (300K); Vₘₚ of H₂(300K); Vₘₚ of O₂(400K)
(B) Vₘₚ of H₂ (300K); Vₘₚ of N₂(300K); Vₘₚ of O₂(400K)
(C) Vₘₚ of O₂ (400K); Vₘₚ of N₂(300K); Vₘₚ of H₂(300K)
(D) Vₘₚ of N₂ (300K); Vₘₚ of O₂(400K); Vₘₚ of H₂(300K)

Answer 1

Answer:

C. will be correct answers

Explanation:

Vmp is inversely proportional to molecular weight.

hope the answer will help you Mark

Answer 2

$\sf\pink{U_{mp} = \sqrt{\dfrac{2RT}{M}}}$

$\sf\green{So,}$

$\sf\green{U_{mp} ∝ \dfrac{1}{M}}$

$\sf{M → Molecular \:weight}$

$\sf\green{i.e \: “Increase \:in \:mass\: or\: Molecular\: weight \:,}$ $\sf\green{result\: decrease\: in \:speed \:and \:vice \:versa.”}$

$\sf\blue{Thus,\: Option \:(D)\: is \:Correct.}$