Question

Points L, M, N are collinear such that d(L,M) = 9.5, d(M,N) = 7.8, find d(L,N) .​

Answer 1

D(L,M) = d(xy)
D(M,N) = d(xz)
D(L,N) = ?

Here

D(x/y)=D(y/z)=D(x/z)
9.5=D(y/z)=7.8
95/10=D(y/z)=78/10
D(y/z)=950/780
D(y/z)=135.71

Hope it’s true (Thank You ;-( )

Answer 2

Answer:

D(L,M)=D(yz). D(M,N)=D(XY). D(L,N)=? here,.

D(X/Y)=D(Y/Z)=D(X/Z)

9.5=D(Y/Z),=7.8

95/10=D(Y/Z)=78/10

D(Y/Z)=950/780

D(Y/Z)=135.71