Math, asked by singhkedar715, 1 year ago

Points P and Q lie on side AB and AC of triangle ABC respectively such that segment PQ is parallel to side BC. If the ratio of areas of triangle APQ: triangle ABC is 25:36. Then the ratio of AP:PB is_____________.

Answers

Answered by SRK1729
1

its easy

we know ratio of areas of similar triangles equales to square of there side proportion

so here ABC and APQ is similar, by AAA similarity

so , 25/36= AP^2/AB^2

5/6= AP/AB

or AB/AP = 6/5

or 1+PB/AP =6/5

or PB/AP= 1/5

0r AP/PB =5

or AP:PB = 5:1

Answered by Anonymous
1

Answer:

AP:PB=5:1

Step-by-step explanation:

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