Question

Points P and Q trisect the line segment joining the points A(0,8) and B(6,-4), then distance AP is, considering P to be near to A is
1)6 units
2)8 unit
3) 2√5 unit
4)2√2 unit​

Answer 1

Answer:

THE ANSWER IS (3) 2√5 unit

EXPLANATION ::

Points P and Q trisect the line segment joining the points A( 0,8) and B(6,-4) such that P is near to A.

P divides line joining the points A( 0,8) and B(6,-4) in the ratio of 1 : 2

So co-ordinate of P is

= (1×6 + 2× 0 /1+2, 1×-4 +2×8 /1+2)

=(2, 4)

So

AP = √ ( 2 - 0) ² + ( 8 - 4) ²

= √2² + 4²

= 2√5 unit

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