Polarized light passes through a polarizer, and only 20% gets through. find the angle between the light's electric field and the polarizer's transmission axis
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2
according to Malus's law,
I = I₀cos²Θ
here, I is the intensity of light that gets through,
I₀ is the intensity incident on polarizer and Θ is the angle between light's electric field and the polarzer's transmission axis.
here, I = 20% of I₀ = 0.2I₀
so, 0.2I₀ = I₀cos²Θ
⇒ 0.2 = cos²Θ
⇒ Θ = cos⁻¹(√0.2)
I = I₀cos²Θ
here, I is the intensity of light that gets through,
I₀ is the intensity incident on polarizer and Θ is the angle between light's electric field and the polarzer's transmission axis.
here, I = 20% of I₀ = 0.2I₀
so, 0.2I₀ = I₀cos²Θ
⇒ 0.2 = cos²Θ
⇒ Θ = cos⁻¹(√0.2)
Answered by
4
As Light is Polarized, we use Malus Law:
I=I₀Cos²θ
where θ is the angle between the light's electric field and the polarizer's transmission axis.
I=Intensity of light that passes through.
I₀=Intensity of light that is incident on polarizer.
According to given :only 20% gets through.
I=20%I₀
I=[20/100 ]xI₀
I=0.2I₀
0.2I₀=I₀ Cos²θ
0.2=Cos²θ
θ=Cos⁻¹(√0.2)
I=I₀Cos²θ
where θ is the angle between the light's electric field and the polarizer's transmission axis.
I=Intensity of light that passes through.
I₀=Intensity of light that is incident on polarizer.
According to given :only 20% gets through.
I=20%I₀
I=[20/100 ]xI₀
I=0.2I₀
0.2I₀=I₀ Cos²θ
0.2=Cos²θ
θ=Cos⁻¹(√0.2)
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