Question

pole of height 58 m and 10m stand upright on the ground the distance them begin 14m find the length of the wire stretched from the top of one ball to the top of of the other pole​

please give full answer with steps ​

Answer 1

GIVEN :-

• Pole of height 58 m and 10 m stand upright on the ground.
• The distance between them is 14 m.

TO FIND :-

• The length of the wire stretched from the top of one pole to the top of another pole , AE.

CONSTRUCTIONS :-

• Draw a line AB ⟂ BC , such that AD = BC.

SOLUTION :-

As we know that,

⇻ AB = DC = 14 m.

✭ Length of EB,

➟ EB = EC - BC

➟ EB = EC - AD

➟ EB = 58 - 10

➟ EB = 48 m.

✪ In ∆ ABE By Pythagoras Theorem,

➙ (AE)² = (AB)² + (BE)²

➙ (AE)² = (14)² + (48)²

➙ (AE)² = 196 + 2304.

➙ (AE)² = 2500

➙ AE = √2500

➙ AE = 50 m.

Hence the length of wire stretched is 50 m.

Answer 2

$\huge \mathbb{\underbrace{\red{Question\:}}}$

Pole of height 58 m and 10m stand upright on the ground the distance them begin 14m find the length of the wire stretched from the top of one ball to the top of of the other pole.

$\huge \mathbb{\underbrace{\red{Solution\:}}}$

We have,

Two poles A and B of height 58m and 10m

Given,

➣ AB = DC = 14 m.

We have to find the length of EB

➣ EB = 58 - 10

➣ EB = 48 m.

By using Pythagoras theorem we can find the length of AE.

➣ (AE)² = (BE)² + (AB)²

➣ AE = √(48)² + (14)²

➣ AE = √2304 + 196

➣ AE = √2500

➣ AE = 50 m.

★ Hence Verified