Poly. axcube+3xsquare-13 and 2xcube-5x+a leave the same remainder when divided by x-2 find value of a
Answers
Answered by
4
polynomial =ax^3+3x^2-13
g(x)=x-2,x=2
put p(x)=2
p(2)=a(2)^3+3(2)^2-13
p(2)=a8+3*4-13
p(2)=a8+12-13
p(2)=a8-1
p(x)=2x^3-5x+a
g(x)=2
put p(x)=2
p(2)=2(2)^3-5*2+a
p(2)=2*8-10+a
p(2)=16-10+a
p(2)=6+a
a8-1=6+a
a8-a=6+1
a7=7
a=7/7
a=1
value of a=1
g(x)=x-2,x=2
put p(x)=2
p(2)=a(2)^3+3(2)^2-13
p(2)=a8+3*4-13
p(2)=a8+12-13
p(2)=a8-1
p(x)=2x^3-5x+a
g(x)=2
put p(x)=2
p(2)=2(2)^3-5*2+a
p(2)=2*8-10+a
p(2)=16-10+a
p(2)=6+a
a8-1=6+a
a8-a=6+1
a7=7
a=7/7
a=1
value of a=1
Similar questions