Question

polygon has 27 diagonals. how many sides does it have​

Answer 1

Step-by-step explanation:

no of diagonal =n(n-3)/2

27=n2-3n/2

27*2=n2-3n

n2-3n-54=0

n2-9n+6n-54=0

n(n-9)+6(n-9)=0

(n+6)(n-9)=0

so no of side of polygon=9

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