Polynomial (2x²+2) is divided
6Y (x+2) then
the remainder
is
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Answer:
:0
Step-by-step explanation:
Given polynomial is √3x² - 5x
To find its zeroes lets equate the polynomial to zero
=> √3x² - 5x = 0
Taking x common
=> x (√3x - 5) = 0
=> x = 0 , √3x - 5 = 0
=> x = 0 , x = 5/√3
The zeroes of polynomial √3x² - 5x are 0 & 5/√3
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