Question

Polynomial 3x^2+6x+3 has only real roots condition

Answer 1

Answer:-1,-1

Step-by-step explanation:

3x²+6x+3

to have real roots

D≥0

b²-4ac≥0

(6)²-4(3)(3)≥0

36-36≥0

0=0  therefore D=0

∴the polynomial has real and equal roots.

by quadratic formula,

x=-b±√D

     2a

x=-6±√0

      2(3)

x=-6

    6

x=-1

therefore the zeroes of the polynomial are -1,-1.