Math, asked by debruchi2706, 1 year ago

polynomial 3x^3-5x^2+kx-2 and -x^3-x^2 + 7 x + k have the same remainder when divided by x + 2. find the value of k.

Answers

Answered by sru8
30
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Answered by hukam0685
5

Value of k is -12.

Given:

  • 3 {x}^{3}  - 5 {x}^{2}  + kx - 2 and  -  {x}^{3}  -  {x}^{2}  + 7x + k
  • Both have the same remainder when divided by (x+2).

To find:

  • Find the value of k.

Solution:

Concept/Theorem to be used:

  • Apply remainder theorem
  • Remainder Theorem: It states that if p(x) is divided by (x-a), then p(a) will be the remainder.

Step 1:

Find value of x from divisor polynomial.

(x + 2) = 0 \\

or

\bf x =  - 2 \\

Step 2:

Put x= -2 in first polynomial; let the first polynomial is p1(x).

p_1( - 2) = 3 {( - 2)}^{3}  - 5 {( - 2)}^{2}  + k( - 2) - 2 \\

or

p_1( - 2) =  - 24  - 20   - 2k - 2 \\

or

\bf p_1( - 2) =  - 46   - 2k ...eq1 \\

Step 3:

Put x=-2 in second polynomial p2(x).

p_2( - 2) = -  {( - 2)}^{3}  -  {( - 2)}^{2}  + 7( - 2) + k \\

or

p_2( - 2) = 8  -  4   - 14 + k \\

or

\bf p_2( - 2) =  k  - 10...eq2\\

Step 4:

Equate both equations.

 \bf p_1( - 2) = p_2( - 2) \\

or

 - 46 - 2k = k - 10 \\

or

 - 2k - k =  - 10 + 46 \\

or

 - 3k = 36 \\

or

k =  -  \frac{36}{3}  \\

or

\bf \red{k =  - 12} \\

Thus,

Value of k is -12.

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