English, asked by marjoriesequeira80, 11 months ago

polynomial equation whose roots are alpha,beta,gamma ​

Answers

Answered by Anonymous
2

Answer:

ax³+ bx² + cx + d = 0

cubic polynomial.

PLZ THANKS ME................

Answered by mdimtihaz
0

Given: Roots of the equation are \alpha,\ \beta,\ \gamma.

The roots can be written as,

(x-\alpha)=0, \ (x-\beta)=0, \ (x-\gamma)=0

So we can write as,

(x-\alpha)\ (x-\beta) \ (x-\gamma)=0\\(x^2-\alpha x-\beta x+\alpha\beta)(x-\gamma)=0\\x^3-\alpha x^2-\beta x^2+\alpha\beta x -\gamma x^2-\alpha \gamma x-\beta \gamma x-\alpha\beta\gamma=0\\x^3- x^2(\alpha +\beta +\gamma )+x(\alpha\beta -\alpha \gamma -\beta \gamma)-\alpha\beta\gamma=0\\

#SPJ3

Similar questions