Math, asked by 57996, 22 hours ago

polynomial factorise 3x² - x - 4 pls solve like this
And pls tell me how you got 4x and 3x ​

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Answers

Answered by twinklingstar19
2

Answer:

The \: radius \: of \: upper \: cone (R _{1}) = \frac{4}{2 } = 2Theradiusofuppercone(R

1

)=

2

4

=2

Bottom radius 4cm

Volume \: of \: upper \: cone (V _{1}) = \frac{1}{3)} \pi r^{2} hVolumeofuppercone(V

1

)=

3)

1

πr

2

h

= \frac{1}{3} \pi \times ({2}^{2}) \times ( \frac{h}{2} )=

3

1

π×(2

2

)×(

2

h

)

Vol \: of \: bottom \: frustum (V_{2}) = \frac{\pi h}{3} (R \frac{2}{1} R \frac{2}{2} + R _{1}R _{2})Volofbottomfrustum(V

2

)=

3

πh

(R

1

2

R

2

2

+R

1

R

2

)

= \frac{\pi( \frac{h}{2}) }{3} (28)=

3

π(

2

h

)

(28)

Vol \: of \: bottom \: frustum (V _{2}) = \frac{\pi h}{6} (28)Volofbottomfrustum(V

2

)=

6

πh

(28)

\frac{V _{1} }{ V_{2} } = \frac{2\pi h}{3} \times \frac{6}{\pi h \times 28}

V

2

V

1

=

3

2πh

×

πh×28

6

\frac{V _{1}}{V _{2}} = \frac{2\pi h}{3} \times \frac{6}{\pi h \times 28}

V

2

V

1

=

3

2πh

×

πh×28

6

\frac{V_{1} }{ V_{2} } = \frac{1}{7}

V

2

V

1

=

7

1

❥ the above is the answer of your question

❥ hope that's helps you

Answered by kartikallinone
0

Answer:

your answer is (3x-4)(x+1)

3x²-x-4

{we can write -x as 3x-4x}

3x²+3x-4x-4

3x(x+1)-4(x+1)

(3x-4)(x+1)

plz mark me as branliest . ....

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