Polynomial p of x is equal to x square + bx + c if a + b + c is equal to zero then find one of its zeros
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hey here is your answer
hope you like this answer
P(x ) = ax² + bx + c
put x = 1
P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )
make it brainliest
hope you like this answer
P(x ) = ax² + bx + c
put x = 1
P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )
make it brainliest
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