Polynomial p(x) =2x cube +kxsquare -3x+5 and q (x) =x cube +2x square -x+k when divided by x-2 leave the remainder r1 and r2 respectively . Find the value of k if r1-r2 =0
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Answered by
8
Answer:
k=1/3
Step-by-step explanation:
x-2=0
x=2
p(x)=2x^3+kx^2-3x+5
p(2)=2(2)^3+k(2)^2-3(2)+5
=16+4k-6+5
=15+4k=r1
q(x)=x^3+2x^2-x+k
q(2)=(2)^3+2(2)^2-2+k
=8+8-2+k
=14+k=r2
r1-r2=0
15+4k-(14+k)=0
15+4k-14-k=0
1-3k=0
-3k=-1
k=-1/-3
K=1/3
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0
Answer:
Step-by-step explanation:
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