Question

polynomial whose zeros are√2 and -√2​

Answer 1

Given :- $\frac{2}{3} (9(3) \: + (3)(5) \: )$

To Find :- $\frac{2}{3} (9(3) \: + (3)(5) \: ) =?$

Solution :-

$\frac{2}{3} (9(3) \: + (3)(5) \: )$

$= \frac{2}{3} (27 \: + 15)$

$= \frac{2}{3} \times 42 \: = 2 \times 14 = 28$

Hence, $\frac{2}{3} (9(3) \: + (3)(5) \: ) = 28$

Hence, the final answer is 28.