Question

Polynomial (x-1)(X+2)(X+3) has how many zeroes?

Answer 1

Answer:

3 zeros

if i am right

Step-by-step explanation:

$(X-1)(X+2)(X+3)\\=(X^{2} + 2X-X-2)(X+3)\\=(X^{2} +X-2)(X+3)\\=X^{3}+3X^{2}+X^{2}+3X-2X-6\\= X^{3}+4X^{2}+X-6$

SO AS THE HIGHEST POWER IS 3 THERE ARE 3 ZEROS!!

HOPE IT HELPS!!!!

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