Question

POLYNOMIALS
19-20
3. If the zeroes of the polynomial x - 3x2 + x + 1 are a - b, a, a + b, find a and b.​

Answer 1

Answer:

Sum of zeroes = - B/A

a - b + a + a + b = -(-3)/1

3a = 3

a = 1.

Product of zeroes = -D/A

(a - b )×a × (a + b) = -1

(1 - b)×1×(1+b) = - 1

$1 - {b}^{2} = - 1 \\ {b}^{2} = 2 \\ b = \sqrt{2} \: or \: - \sqrt{2}$

Answer 2

Answer:

this is correct.........................