polynomials
4x² – 3x + 7
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2
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
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