Math, asked by manishaqueen, 6 months ago

Polynomials and Their Factors
24. Subtract the second polynomial from the first in the follo
(i) x3 + x +1; 1- x - x2
(ii) 6x3 + 5x
(iii) x3 + x2 + x + 1; X3 - x2 + x - 1 (iv) x4 - 3x
(v) 3x7 - 2x2 + 3; x6 - 3x4 + x2 + x
25. Find the product of the following polynomials :
(i) x2 - 4x + 4; x-2
(ii) x2 + 3x
(iii) 3x3 + x2 + x; x + 2
(iv) 3x + 2;​

Answers

Answered by aditya738451396
0

Answer:

ANSWER

Apply remainder theorem

x+1=0

x=−1

Put the value of x=−1 in all equations.

(i) x

3

+x

2

+x+1=(−1)

3

+(−1)

2

+(−1)+1=−1+1−1+1=0

Then x+1 is the factor of equation

(ii) x

4

+x

3

+x

2

+x+1=(−1)

4

+(−1)

3

+(−1)

2

+(−1)+1=1−1+1−1+1=1

This is not zero.Then x+1 is not the factor of equation

(iii) x

4

+3x

3

+3x

2

+x+1=(−1)

4

+3(−1)

3

+3(−1)

2

+(−1)+1=1

This is not zero.Then x+1 is not the factor of equation

(iv)x

3

−x

2

−(2+

2

)x+

2

=(−1)

3

−(−1)

2

−(2+

2

)(−1)+

2

=−1−1+2−

2

+

2

=0

This is zero. Then x+1 is the factor of equation

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