Math, asked by rajeshsagarlalganj, 7 months ago

Polynomials
. Verify that
(i) 1 and 2 are the zeros of the polynomial, p(x) = x2-3x + 2.
(ii) 2 and 3 are the zeros of the polynomial, q(x) = x²+x-6.
(iii) 0 and 3 are the zeros of the polynomial, r(x) = x2-3x.
Find the zero of the polynomial:
(i) p(x) = x-5 (ii) 9(x) = x+4 (iii) r(x) = 2x +​

Answers

Answered by sanayafaiz
2

Answer:

1.p(x)=x2-3x+2

p(1)=1(2)-3(1)+2

     =2-3+2

     = 7-3

      4

Step-by-step explanation:

Answered by pawanag1012
1

P(1) = (1)2-3(1) + 2

= 2 - 3 + 2

= -1 +2

= 1 is answer

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