Math, asked by vickyaicky274, 1 year ago

Pooja and ritu can do a piece of work in 17 1/7 days.if one day work of pooja be three fourth of one day work of ritu;find in how many days each will do the work alone?

Answers

Answered by victory1venkatesh
34
Let the work done by pooja be x 
Let the work done by ritu. be y 
So x + y = 17
Condition is
3/4y + y = 17
7y = 68 
y = 9.7 days 
x + 9.7 = 17
x = 7.3 days 
Answered by febinsheza
72

Answer:

Step-by-step explanation:

1/x + 1/y =7/120

1/x =3/4×1/y

3/4y +1/y=7/120

(3+4)/4y =7/120

7/4y=7/120

1/4y=7/(120×7)

120/4=y

30=y

1/x=3/4y

1/x=3/(4×30)

1/x=1/40

x=40

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