Question

POOJA GOT A NEW ROOM HEATER FOR HER BEDROOM.THE TEMPERATURE OF THE ROOM RISES BY 2 DEGREE CELSIUS IF THE HEATER RUNS FOR 3 MINUTES.AFTER EVERY 3 MINUTES,THE HEATER STOPS FOR A MINUTE AND THE TEMPERATURE FALLS BY 1 DEGREE CELSIUS.IF THE PRESENT ROOM TEMPERATURE IS 12 DEGREE CELSIUS ,FIND OUT AFTER HOW MUCH TIME THE TEMPERATURE BECOMES 38 DEGREE CELSIUS.

Answer 1

Step-by-step explanation:

Let the temperature of the heater be, T

Let the temperature of the heater be, T o

Let the temperature of the heater be, T o C

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 =

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10 Solving the above equation for T, gives us T=60

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10 Solving the above equation for T, gives us T=60 o

Let the temperature of the heater be, T o CNow, if the above conditions satisfy, then,−20−20T−20 = −40−10T−10 Solving the above equation for T, gives us T=60 o C