Question

Pooja runs around a rectangular field of 70cm
by 42 cm. She takes 5 rounds. How much distance
does she covered?​

Answer 1

Answer:

• She covered 1120 cm of distance.

Step-by-step explanation:

Given that:

Pooja runs around a rectangular field.

• Length of the field = 70 cm
• Breadth of the field = 42 cm

Formula used:

Perimeter of rectangle = 2(L + B) unit

Where,

• Length is denoted by L.
• Breadth is denoted by B.

Finding the length of one round of the rectangular field:

→ Perimeter of rectangle = 2( 70 + 42) cm

→ Perimeter of rectangle = 2 × 112 cm

→ Perimeter of rectangle = 224 cm

∴ The length of one round of the rectangular field = 224 cm

To find:

• How much distance does she covered?

Given: She takes 5 rounds.

Finding the length of five round of the rectangular field:

One round of rectangular field = 224 cm

∴ Five round of rectangular field = (224 × 5) cm

∴ Five round of rectangular field = 1120 cm

Answer 2

Step-by-step explanation:

${\large{\bold{\rm{\underline{Understanding\ the\ concept\ 1^{st}}}}}}$

★ This question says that Pooja runs around a rectangular field whose length is 70cm and breadth is 42cm. So first we will find the length of one round of the rectangular field. Then we easily find out the distance covered by Pooja by multiplying the length of first round with total number of rounds. So let's do....!!!

${\large{\bold{\rm{\underline{Given\ that}}}}}$

$\sf {\bigstar Length\ of\ the\ rectangular\ field\ =\ 70cm.}$

$\sf {\bigstar Breadth\ of\ the\ rectangular\ field\ =\ 42cm.}$

${\large{\bold{\rm{\underline{To\ find}}}}}$

★ Distance covered by pooja ?

${\large{\bold{\rm{\underline{Using\ formula}}}}}$

$\star\;\boxed{\bf{\pink{Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}}$

Where,

• L, is for length.
• B, is for breadth.

${\large{\bold{\rm{\underline{Solution}}}}}$

★ The total distance covered by Pooja is 1120cm.

${\large{\bold{\rm{\underline{Full\ solution}}}}}$

$\sf : \implies {Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}$

$\sf : \implies {Perimeter\ of\ rectangle\ =\ 2(70\ +\ 42)\ cm}$

$\sf : \implies {Perimeter\ of\ rectangle\ =\ 2(112)\ cm}$

$\sf : \implies {Perimeter\ of\ rectangle\ =\ 2 \times 112\ cm}$

$\sf : \implies {Perimeter\ of\ rectangle\ =\ 224cm.}$

∴ The length of one round of the rectangular field = 224cm.

~Since, we have to find the distance covered by Pooja. Now we have the length of one round of the rectangular field that is 224cm. So, we will find out the distance covered by Pooja by multiplying the length of one round of the rectangular field with no. of rounds.

$\sf : \implies {Length\ of\ one\ round\ of\ rectangular\ field\ =\ 224cm}$

$\sf : \implies {Five\ round\ of\ rectangular\ field\ =\ 224 \times 5}$

$\sf : \implies {Five\ round\ of\ rectangular\ field\ =\ 1120cm.}$

∴ Hence, the distance covered by Pooja is 1120cm.

${\large{\bold{\bf{\underline{More\ to\ know}}}}}$

● Diagram of rectangle:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large y cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\bf \: \: \: \: \: \: \: \: \: \: \: \: \: \leadsto {Area\ of\ rectangle\ =\ length \times breadth}$

$\bf \: \: \: \: \: \: \: \: \: \: \: \: \: \leadsto {Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}$

● Properties of rectangle:

• The opposite sides are parallel and equal to each other.
• Each interior angle is equal to 90°.
• The diagonals bisect each other.
• Both the diagonals have the same length.
• The diagonals bisect each other at different angles. One is acute, and another one is an obtuse angle.
• If the two diagonals bisect each other at right angles, then the rectangle is known as a square.