pooja walking at 4 km/hr reaches her school 5 minutes late. If she walks at 5km/hr, she will reach her school 4 minutes early. find the distance of her school from her residence
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let the distance b x km
time taken at 4 km/h = x/4
time taken at 5 km/h = x/5
but the difference in those two times is 9 minutes
or 9/60 hrs = 3/20 hrs
x/4- x/5 = 3/20
times 20, the LCD
4x - 4x = 3
x = 3
time taken at 4 km/h = x/4
time taken at 5 km/h = x/5
but the difference in those two times is 9 minutes
or 9/60 hrs = 3/20 hrs
x/4- x/5 = 3/20
times 20, the LCD
4x - 4x = 3
x = 3
manavi:
thanks
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