Pooja wants to draw an equilateral triangle wjose perimeter is equal to 45 cm. What would be the measure of each side of the triangle
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- In an equilateral ∆ since all sides are the same
- So let the measure of one side be = a
Therefore perimeter of the ∆;
- P = s + s + s
- P = 3s
Given that perimeter (P) = 45cm;
- P = 3s
- 45 = 3s
- s = 15cm
Thus measure of each side of the ∆ be 15 cm
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Answer:
I think
Step-by-step explanation:
think side must be 15cm each .... because perimeter is 3x side
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