Question

poonam invested an amount of r.s 35000 for two years at the rate of 5 percentage per annum . what amount compound interest would she receive at the end of 2 years.​

Answer 1

C.I =P((1+i)^n_1) p=5%

i=5÷100

i=0.05

C.I=35000((1+0.05)^2_1)

=35000((1.05)^2_1)

=35000(1.1025_1)

=35000(0.1025)

=3587.5

Answer 2

Answer:

$p = rs.35000 \\ r = 5\%p.a \\ t = 2 \: years \: \\ \\ ci1 = \frac{p \times r \times t}{ 100} = \frac{35000 \times 5 \times 1}{100 } = 1750 \\ \\ p2 = 35000 + 1750 = 36750 \\ \\ ci2 = \frac{p \times r \times t}{100} = \frac{35000 \times 5 \times 1}{100} = 1837.5 \\ \\ p3 = 35000 + 1837.5 = 36837.5 \\ \\ total \: amount \: = \: 36837.5 - 1750 \: = \: 35087.5 \: answer \: \: \\ \\ \\ \\ \\ \\ \\ follow \: me \: please \: please \: please \: = \: requesting$

follow me plz plz plz plz plz plz