Math, asked by harshadsule600, 3 months ago

population of a city in a specific year was 80000 there was rise 10% for each of the next 3 years the population at the end 3 years is​

Answers

Answered by jlikithgopal
2

Answer:

initial population = 80000

:population in next year =80000+80000×10÷100 =88000

:population aft 2nd year =88000+88000×10÷100=96,800

:population aft 3rd yr= 96800+96000×10%=106,480.= Ans

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