Math, asked by harshadsule600, 3 months ago

population of a city in a specific year was 80000 there was rise 10% for each of the next 3 years the population at the end 3 years is​

Answers

Answered by aniketbohra202
3

Answer:

the original population = 80000

rise in population per year = 10% of the previous year

Step-by-step explanation:

therefore for the first year

rise in population is 10/100 * 80000

= 8000

so the new population is 80000 + 8000 = 88000

the rise in ppl in the next year 10/100 * 88000

=8800

so the population at the end of the 2nd year is 88000+8800 = 96800

the rise in ppl in the 3rd year 10/100 * 96800

=9680

the final population at the end of three years is 96800 + 9680 =106480

Similar questions