population of a city in a specific year was 80000 there was rise 10% for each of the next 3 years the population at the end 3 years is
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Answer:
the original population = 80000
rise in population per year = 10% of the previous year
Step-by-step explanation:
therefore for the first year
rise in population is 10/100 * 80000
= 8000
so the new population is 80000 + 8000 = 88000
the rise in ppl in the next year 10/100 * 88000
=8800
so the population at the end of the 2nd year is 88000+8800 = 96800
the rise in ppl in the 3rd year 10/100 * 96800
=9680
the final population at the end of three years is 96800 + 9680 =106480
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