Math, asked by nishant44, 1 year ago

population of a city increase at a rate of 9% every year. what was the population of the city 2 year ago if it's present population is 2800000

Answers

Answered by anay7
3
2754000 is right answer
Answered by manavkadam
15
so this is CI question you first simply calculate CI on population SI=2800000×9×1/100
= 25200
SUBSTRACT this SI from population i.e p-SI=2800000-25200
=2774800.
now again take SI of it
=2774800×9÷1/100
=249732
now SUBSTRACT it from seconď SI
2774800-248732
=2526068 is the population 2 years before.
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