population of a city reduced by 10% due the flood . if its present population is 1422000 . what was the population a year ago
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Answered by
23
Let population previous year be x
Present population = population previous year - 10% of population previous year
1422000 = x - 10% of x
1422000 = x - x/10
1422000 = 9x/10
1422000×10/9 = x
x = 1580000
Therefore, population previous year was 1580000
Present population = population previous year - 10% of population previous year
1422000 = x - 10% of x
1422000 = x - x/10
1422000 = 9x/10
1422000×10/9 = x
x = 1580000
Therefore, population previous year was 1580000
Answered by
5
Answer:
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Step-by-step explanation:
Let the population of a city a year ago be X.
Present population = previous population - 10% of previous population.
then, 14,22,000 = x - 10% of x
14,22,000 = x-1/10x
14,22,000 = 9x/10
14,22,000 × 10/9 = x
15,80,000 = x
th population of a city a year ago = 15,80,000
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