Question

population of a city was 8,60,000.in next year it is increased by 14,000 more than one tenth of the previous population the present population in the city is (plz tell me how to solve)

Answer 1

Let the present population of the city be y.

Given,y = (The previous population)+(1/10)(The previous Population)+14000

Therefore,

y = 860000 + [(1/10) x 860000] + 14000
y = 860000 + 86000 + 14000
y = 860000 + 100000
y = 960000

Therefore the present population of the city is 9,60,000.


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Answer 2

Let the present population in the city = x.

Given that population of a city was 860000.

Given that in next year it is increased by 14000 more than 1/10th of the previous population.

x - 860000/10 = 14000

x - 86000 = 14000

x = 14000 + 86000

x = 100000.


Therefore the present population in the city = 100000.


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