population of a town increases by 10.5% every year if its present population is 795600 what was it a year ago
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Let the population of town a year ago be x.
Therefore, x+(10.5%of x) = 795600
x+105x/1000 = 795600
1105x/1000 = 795600
1105x = 795600×1000
x = 795600000/1105 = 72,000
Hence, the population a year ago was 72,000 .... Hope that helps
Therefore, x+(10.5%of x) = 795600
x+105x/1000 = 795600
1105x/1000 = 795600
1105x = 795600×1000
x = 795600000/1105 = 72,000
Hence, the population a year ago was 72,000 .... Hope that helps
abcd57:
unfortunately this answer is wrong
yes! i did corrected that after editing. I misunderstood 10.5 as 10
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