Question

Population of a town increases by 15% per year if the population of that town is 10, 36, 725
this year, what was the population in the previous year?
A9,01,530
B 10, 20, 500
C 9,01,500
D10, 36, 710

Answer 1

Answer:

i hope it will help you

in your future

Answer 2

Answer:

We can find the previous year population using the current year population and the increasing percentage(15%).

Answer: Option c: Population of the previous year $x=9,01,500$

Step-by-step explanation:

From the given question,

Population of the previous year = $x$

Population increasing Percentage per year $=15$%

Population of the current year $=10,36,725$

• Using the above given data we can find population in the previous year.
• For that we should add previous year population and 15% of previous year population.That addition value is equal to the cuurent year population.

Equation is,    $x+ x$ of 15% $=10,36,725$

                      $x+(x\times\frac{15}{100} )=10,36,725$

• Now take  $x$ is a common term in Left Hand Side(L.H.S)

                          $x(1+\frac{15}{100} )=10,36,725$

• Take the L.C.M for $1$ and $100$ in the denominator in L.H.S.So that,

                        $x(\frac{100}{100}+\frac{15}{100} )=10,36,725$

                             $x(\frac{100+15}{100} )=10,36,725$

                                  $x(\frac{115}{100} )=10,36,725$

                                          $x=10,36,725\times\frac{100}{115}$

• If we divide $10, 36, 725$ by $115$,then we get the following equation.

                                           $x=9015\times100$

                                           $x=9,01,500$

Answer: Population of the previous year $x=9,01,500$