Question

Population of a town increases every year by 5%.what is the population after 2 years if the present population is 540000

Answer 1

let the population be x

thus

increase per year
= 5% of x

increase for two years = 10% of x


but

x = 540000 ...........given

thus

$increase = \frac{10}{100} \times 540000 \\ \\ = 54000$
thus


population after 2 years = original population + increase


=. 540000+54000

= 594000



thus

Population after 2 years is 594000

Answer 2

population after 2 years =P×(1+R/100)^n This is formula
P=population of town
R=increase percentage
n=number of years

now solve the sum

population after two years=P×(1+R/100)^n

P = 540000
R = 5%
n = 2
=540000×[1+(5/100)]^2
=540000×(105/100)^2
=540000×105/100×105/100
=54×105×105
=54×11025
=595350