Question

Population of a town is 1,30,000. if males are increased by 11% & females are increased by 16% then population is increased by
by 17,800 after 1 yrar. Catulate initial number of males in town.​

Answer 1

Answer:

147800 is the answer hope you understand

Answer 2

$\underline{\boxed{\bold{Question}}}$  

↠ Population of a town is 1,30,000. If males are increased by 11% & females are increased by 16% then population is increased by  17,800 after 1 year. Calculate initial number of males in town.​

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$\underline{\boxed{\bold{Important\;Information}}}$  

↠ This question is based on basic Mathematics. We need to to add Quantities accordingly.

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$\underline{\boxed{\bold{Given}}}$

↠ Initial population = 1,30,000

↠ Increase in percentage of males = 11%

↠ Increase in percentage of = 16%

↠ Increase in population of = 17,800

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$\underline{\boxed{\bold{To \; Find}}}$

↠ Initial population of males = ?

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$\underline{\boxed{\bold{Answer}}}$

Let's Start !

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Let's Assume the given information as follows :

$\boxed{\bold{Initial\;Population\;of\;Males = x}}$

$\boxed{\bold{Initial\;Population\;of\;Females = y}}$

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∴ By initial given conditions,

$:\implies Total\;population = x + y$

$\boxed{:\leadsto\; x + y = 1,30,000}$                        (Equation 1)

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Now,

Percentage increase in males = 11%

Population of males after year is :

$:\implies New \;Male\;Population = x + x(\frac{11}{100})$

$\boxed{:\implies New \;Male\;Population = (\frac{111x}{100})}$

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Now,

Percentage increase in females = 16%

Population of males after year is :

$:\implies New \;Female\;Population = x + x(\frac{16}{100})$

$\boxed{:\implies New \;Female\;Population =(\frac{116x}{100})}$

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Now,

Increase in population = 17,800

$:\implies New \;Population =1,30,000 + 17,800$

$\boxed{:\implies New \;Population =1,47,800 }$

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∴ By new year conditions,

$:\implies \frac{111x}{100} + \frac{116y}{100} =1,47,800$

$\boxed{:\leadsto\; 111x + 116y =1,47,80,000}$                 (Equation 2)

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∴ By solving given 2 equations as below,

$:\leadsto\; 111x + 116y =1,47,80,000$

$:\leadsto\; x + y = 1,30,000$

We get,

→ x = 60,000

→ y = 70,000

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$\boxed{\boxed{\bold{\therefore Initial\;Population\;Males=60,000}}}$

$\boxed{\boxed{\bold{\therefore Initial\;Population\;Females= 70,000}}}$

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Hope this helps u.../

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