Question

population of a town is 176400.If it increases at the rate of 5% per annum,what will be its population 2 years hence ? what was it 2 years ago ?

Answer 1

Answer:

Total population in 2 years is 194481.

Total population 2 years ago is 160000.

Step-by-step explanation:

Given : Population of a town is 176400. If it increases at the rate of 5% per annum.

To find : What will be its population 2 years hence?

What was it 2 years ago ?

Solution :

Let P be the population, P=176400

r is the increasing rate, r=5%

t is the time (in years) t=2

It is form by an exponential function represented as

$A=P(1+\frac{r}{100})^t$

$A=176400(1+\frac{5}{100})^2$

$A=176400(1.1025)$

$A=194481$

Total population in 2 years is 194481

Two years ago the population is,

$A=P(1+\frac{r}{100})^t$

$176400=P(1+\frac{5}{100})^2$

$176400=P(1.1025)$

$P=\frac{176400}{1.1025}$

$P=160000$

Total population 2 years ago is 160000.

Answer 2

Answer :-

Principal = 176400

Rate = 5%

Time = 2 years

Population after 1 year :

= 176400 + (5 % of 176400 )

= 176400 + ( 5 / 100 × 176400 )

= 185220

Population after next year :

= 185220 + ( 5 % of 185220 )

= 185220 + ( 5 / 100 × 185220 )

= 194481

Hence, the population is 194481