Math, asked by ranitaranita1999, 3 months ago



Population of a town is 9000. If the males
by 8%. and the females increase
by 5%.the population will be 9600. Then the
number of males of the town initially was​

Answers

Answered by hukam0685
0

The number of males initially was 5000.

Given:

  • The population of a town is 9000.
  • If the males by 8% and the females increase by 5%.
  • The population will be 9600.

To find:

  • Find the number of males in the town initially.

Solution:

Step 1:

Write the equations.

Let the number of men be 'x' and women be 'y'.

\bf x + y = 9000...eq1 \\

And

108\% \: of \: x + 105\% \: of \: y = 9600 \\

 \frac{108}{100} x +  \frac{105}{100}y = 9600 \\

\bf 108x + 105y = 960000...eq2 \\

Step 2:

Solve the equations.

Multiply eq1 by 105 and subtract both equations.

108x + 105y = 960000 \\ 105x + 105y = 945000 \\ ( - ) \:  \:  \: ( - ) \:  \:  \:  \: ( - ) \:  \:  \:  \:  \:  \:  \:  \:  \\  -  -  -  -  -  -  -  -  -  -  -  \\  3x =   15000 \\  -  -  -  -  -  -  -  -  -  -  -

3x = 15000 \\

x =  \frac{15000}{3}  \\

\bf x = 5000 \\

Thus,

The number of males initially was 5000.

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Answered by pulakmath007
0

The number of males of the town initially was 5000

Given :

  • Population of a town is 9000.

  • The males by 8% and the females increase by 5% the population will be 9600

To find :

The number of males of the town initially

Solution :

Step 1 of 2 :

Form the equation to calculate number of males of the town initially

Let number of males of the town initially was n

Since total population of the town = 9000

∴ Number of females of the town initially = 9000 - n

Again males by 8% and the females increase by 5% the population will be 9600

By the given condition

\displaystyle \sf  n \times  \frac{108}{100}  + (9000 - n) \times  \frac{105}{100}  = 9600

Step 2 of 2 :

Calculate number of males of the town initially

\displaystyle \sf  n \times  \frac{108}{100}  + (9000 - n) \times  \frac{105}{100}  = 9600

\displaystyle \sf  \implies  \frac{108n}{100}  +   \frac{105(9000 - n)}{100}  = 9600

\displaystyle \sf{ \implies }108n + 945000 - 105n = 960000

\displaystyle \sf{ \implies }3n = 960000 - 945000

\displaystyle \sf{ \implies }3n = 15000

\displaystyle \sf{ \implies }n = 5000

Hence number of males of the town initially was 5000

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