Question

Population of a town three years ago was 60,000. If the annual increase during three successive years be at the rate of 4%, 5% and 6%, respectively, find its
present population.
​

Answer 1

Answer:

population after first year

$= 60000 \times 1.04 = 62400$

population after second year

$= 62400 \times 1.05 = 65520$

population after third year

$= 65520 \times 1.06 = 69451$

Note:- 69451.2 has been appproximated to 69451