population of a town three years ago was 60000.if the annual increase during 3 successive years is at the rate of 4%,5%and 6%respectively,find the present population?
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Answer:
Step-by-step explanation:
let the population be the principle
P * R* T / 100
for first year it is 4%
60000 * 4 * 1 / 100
=600*4 =2400 people came in first year.
for third year it is 6%
60000 * 6 * 1 / 100
=600 * 6 = 3600 people cane in second year
NOTE THAT HERE I TOOK YEAR 1 BUT IT IS SECOND YEAR. IT IS SO BECAUSE THE YEAR IS SECOND BUT WE HAVE TO TAKE OUT THE RATE OF EVERY YEAR ONE BY ONE.
Now for the second year it is 5%
=60000 * 5 * 1 / 100
=3000 people
now do sum of population increased in all the 3 years
3000 + 3600 + 2400 = 9000 people came in town
*** Now the current population is 60000 +9000 = 69000
the population in town is 69000
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