Question

population of a town three years ago was 60000.if the annual increase during 3 successive years is at the rate of 4%,5%and 6%respectively,find the present population?​

Answer 1

Answer:

Step-by-step explanation:

let the population be the principle

P * R* T / 100

for first year it is 4%

60000 * 4 * 1 / 100

=600*4 =2400 people came in first year.

for third year it is 6%

60000 * 6 * 1 / 100

=600 * 6 = 3600 people cane in second year

NOTE THAT  HERE I TOOK YEAR 1 BUT IT IS SECOND YEAR. IT IS SO BECAUSE THE YEAR IS SECOND BUT WE HAVE TO TAKE OUT THE RATE OF EVERY YEAR  ONE BY ONE.

Now for the second  year it is 5%

=60000 * 5 * 1 / 100

=3000 people

now do sum of population increased in all the 3 years

3000 + 3600 + 2400 = 9000 people came in town

*** Now the current population is 60000 +9000 = 69000

the population in town is 69000

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